How much of the stock solution do you need to add to make 1000 microliters of 1 picomolar plasmid DNA?

In a DNA cloning experiment, the plasmid DNA concentration for the transformation reaction is supposed to be 1 picomolar. A stock solution of 1 micromolar was ordered. How much of the stock solution do you need to add to make 1000 microliters of 1 picomolar plasmid DNA?|||When solutions are diluted or


concentrated, the equality is:





Ms x Vs = M x V


where,


Ms = molarity of stock


Vs = volume of stock


M = new molarity


V = new volume


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For this problem,





M stock x V stock = M plasmid DNA x V plasmid DNA





Solving for V stock:


V stock = (M plasmid DNA x V plasmid DNA) / (M stock) ~(eq1)


where,


M stock = 1 micromolar = 1 碌M = (1x10^-6 M)


M plasmid DNA = 1 picomolar = 1 pM = (1x10^-12 M)


V plasmid DNA = 1000 microliter = 1000 碌L = 1000路(1x10^-6 L)





Substituting numbers into ~(eq1):


V stock = (1 pM x 1000 碌L) / (1 碌M)


canelling-out/dividing 碌





= (1 pM x 1000 L) / (1 M)


canelling-out/dividing M





= 1 p x 1000 L





= 1000 pL





Answer:


*** 1000 pL ***